"""
https://leetcode.cn/problems/reverse-string/description/
344. 反转字符串
简单
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提示
编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。



示例 1：

输入：s = ["h","e","l","l","o"]
输出：["o","l","l","e","h"]
示例 2：

输入：s = ["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]


提示：

1 <= s.length <= 105
s[i] 都是 ASCII 码表中的可打印字符
"""
from typing import List


class Solution:
    def reverseString(self, s: List[str]) -> None:
        """
        Do not return anything, modify s in-place instead.
        """
        center_idx= len(s)//2
        for left in range(center_idx):
            right=len(s)-1-left
            self.swap(s,left,right)


    def swap(self,s:List[str],idx1:int,idx2:int)->None:
        temp=s[idx1]
        s[idx1]=s[idx2]
        s[idx2]=temp



if __name__ == '__main__':
    sol=Solution()

    s = ["H","a","n","n","a","h"]
    sol.reverseString(s)

    print(s)

    pass